The curvature of the helix r(t)equals(a cosine t )iplus(a sine t )jplusbt k (a, bgreater than or equals0) is kappaequalsstartfraction a over a squared plus b squared endfraction . what is the largest value kappa can have for a given value of b?

dsfdsf

step-by-step explanation:

fddsf

answer: 5100 just subtract

step-by-step explanation:

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: