The game of monopoly is played on a square board with 10 spaces per side (so 40 in total). a player starts at the space marked "go" and on each turn rolls two sided dice, advancing forward a number of spaces equal to the sum of the two numbers that lands face up. let p be the probability that a player after they "loop around" the board 10 times, lands on the space "boardwalk" (the 40th square) before they "loop around" the board an eleventh time. which integer is closest to the value 20p?

1e+27

step-by-step explanation:

h= 12 inches

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)