Mathematics, 01.10.2019 20:10 bettymj3071

Two cars are 400km apart. one car is traveling at 55 km/h and the other car is traveling at 45 km/h if they start at the same time and are driving toward each other how long ?

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Two cars are 400 km apart. One car is traveling at 55 km/h and the other car is traveling at 45 km/h if they start at the same time and are driving toward each other, the two cars will meet after 4 hours .

Solution:

Let the two car be A and B.

Given that two cars are 400 km apart.

Let us assume distance travelled by A to meet B = x km

The distance travelled by B can be found out by subtracting the total distance x from distance travelled by A.

So distance travelled by B = (400-x) km

Time taken will be same for A and B

We know that, $\text\bold{ {Speed}=\frac{\text {Distance}}{\text {Time}}}$

So, we get

$\text { Time }=\frac{\text { Distance }}{\text { speed }}$

Let us consider the time taken by car $A=T_{A}$ .So time taken by A to travel x km = $\frac{x}{55}$

Similarly, time taken by B to travel distance (400-x) km = $T_{B}=\frac{400-x}{45}$

When the two cars meet, $\bold{\mathrm{Ta}=\mathrm{Tb}}$ .hence we get,

$\frac{x}{55}=\frac{400-x}{45}$

On solving above equation,

$\frac{x}{55}=\frac{400-x}{45}$

$\frac{x}{11}=\frac{400-x}{9}$

9x = 11(400 – x)

9x = 4400 – 11x

9x + 11x = 4400

20x = 4400

X = 220

After 220 km of travel, the car with speed of 55 km will meet other car travelling with speed of 45 km. now the time taken for two cars to meet each other is given as,

Time taken for cars to meet = $\frac{220}{55}=4$

Hence the two cars will meet after 4 hours.

Answer from: Quest

21.4 i did it already for s1

step-by-step explanation:

Answer from: Quest

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

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