Mathematics, 02.10.2019 17:10 tierrag81

An external sinusoidal force is applied to an oscillating system which can be modelled by a model spring and a damper. the general solution of the equation of the motion is given by, x = 4+ 3.984cos(2nt-b) + 2.81exp(-8.58t)cos(at + o) where a, b, and are some constants. determine the amplitude of the oscillation when steady-state is reached. give your answer correct to 3 decimal places.

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Answer from: AshleyRojas7187

The amplitude of the oscillation in this oscillating system, after reaching the steady-state, is 3.984.

Step-by-step explanation:

Assume you know a and b values, which you do not actually need to know to solve the question.

The given general solution of the equation is made up of three terms, namely:

A constant value (equal to 4),a cosine term: 3.984cos(2nt-B)a cosine, exponential term: 2.81exp(-8.58t)cos(at + o)

This means that, after a certain time (for large values of time "t"), when the system reaches its steady-state, the following will happen to these parts, respectively:

The constant value will remain as 4. It shall not cancel, but it shall not provide any oscillation either, and, in turn, no amplitude nor frequency.The second term will always be a cosine, since it is a periodic function. Its amplitud is "3.984" and its frequency is "2n" radians/second. Its phase is actually "B".This third term is not a periodic functon. It is made up of a periodic function multiplied by an exponential function, whose exponent is negative (for any positive value of time variable "t"). This exponential function approaches to zero when its exponent approaches to minus infinity. So, after a certain time -or, in other words, once the steady-state is eventually reached- the product will be a delimited function (cosine, whose absolute value is always than "1") multiplied by zero. That is, this third term, as a whole, approaches to zero for large, infinite values of time "t".

All in all, once the steady-state is reached, the solution shall remain as:

x = 4+ 3.984cos(2nt-B).

The only oscillation would be that of the cosine term, and its amplitude will be 3.984, an actual value given by the question itself.

Answer from: Quest

stops on an even number.

Answer from: Quest

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

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