C= k - 273.15 (a) write two other related equations . (b) if the temperature is 23 in degrees celsius , what is the temperature in kelvins? show your work. (c) which is greater, 300 kelvins or 25 degrees celsius ? show your work.

The two other related equations are:

k = C + 273.15

    2. k/C = 273.15

K =  C + 273.15

C = 23 degrees

Hence:

K = 23 + 273.15

K = 296.15 K

23 degrees celsius is 296.15 Kelvins

K =  C + 273.15

C = 25 degrees

Hence:

K = 25 + 273.15

K = 298.15 K

25 degrees celsius is 298.15 Kelvins

Therefore, 300 Kelvins is greater than 25 degrees

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(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: