Write the expression as a single natural logarithm.
3 in b - 4 in x

in x^4/b^3
in (b^3-x^4)
in b^3/x^4
in (b^3+x^4)

answer: i think it is (1,-2)

he kicked it up? is this the answer ?

step-by-step explanation:

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.