The non-profit organization you volunteer for is throwing a fundraiser cookout. you are in charge of buying the hamburgers, which cost $3 per pound, and hot dogs, which cost $2 per pound. the meat budget you are given totals $600 dollars. the inequality 3x + 2y less than or equal to 600 represents the possible combinations of pounds of hamburgers (x) and hot dogs (y) you can buy.

Which of the following represents a solution to the inequality?
200 pounds of hamburgers and 140 pounds of hot dogs
150 pounds of hamburgers and 60 pounds of hot dogs
100 pounds of hamburgers and 240 pounds of hot dogs
240 pounds of hamburgers and 40 pounds of hot dogs

x = hamburger ; y = hot dog
3x + 2x < 600

3(200) + 2(140) = 600 + 280 = 880 No.
3(150) + 2(60) = 450 + 120 = 570 YES.
3(100) + 2(240) = 300 + 480 = 780 No.
3(240) + 2(40) = 720 + 80 = 800 No.

150 pounds of hamburgers and 60 pounds of hot dogs 

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)