This problem shows that infinite sets behave differ- ently than the finite ones considered in the previous problem. (i) find a function f: z-> z that is injective, but not surjective. (ii) find a function g: zz that is surjective, but not injective. - (iii) find a proper subset s of z (that is, s is not z itself) and a bijective function h: sz.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

3

step-by-step explanation:

2 x 503

step-by-step explanation:

its 1006