Mathematics, 03.10.2019 00:30 andrewgainey1986
Suppose that (a, m) = 1. if a = +1, the solution of ax = 1 (mod m') is obviously x = a(mod m'). if a = +2, then m is odd and x = (1 - m')}a (mod m') is the solution of ax = 1(mod m'). for all other a use problem 11 to show that the solution of ax = 1(mod m ) is x = k (mod m') where k is the nearest integer to -(1/a)(1 – ax,)'.
Answers: 3
Mathematics, 21.06.2019 15:20
Abcd ≅ klmn ≅ pqrs ≅ wxyz given that information, which figures are reflections of abcd?
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Mathematics, 21.06.2019 18:40
What value of x is in the solution set of 4x – 12 s 16 + 8x?
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Mathematics, 21.06.2019 19:10
Which situation can be modeled by the inequality 5 + 10w ≥ 45? a. you start with $5 and save $10 a week until you have at least $45. b.you start with 5 baseball cards and purchase 10 cards every week until you have at most 45 cards. c.you start with 5 water bottles and purchases cases of 10 water bottles each until you have a total of 45 water bottles. d.you spend $5 plus $10 per week until you have less than $45.
Answers: 3
Mathematics, 21.06.2019 20:30
choose the correct definition for extremo. a. end b. extra c. extract d. eventual
Answers: 2
Suppose that (a, m) = 1. if a = +1, the solution of ax = 1 (mod m') is obviously x = a(mod m'). if a...
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