What is the area of a rectangle with vertices (-8, -2), (-3,-2), (-3,-6), and (-8. -6)?
square units

31 square units

The area of the rectangle is 20 sq .units.

(-8, -2), (-3,-2), (-3,-6), and (-8, -6)

The area of the rectangle ‘A’ is given by the formula:

Area = Length × Width

Now, we have to find the sides of the rectangle.

The sides of the rectangle include s1, s2, s3, and s4.

Let’s now assume the points as:

The side s1 is:

On substituting the values,

The side s2 is:

On substituting the values,

The side s3 is:

On substituting the values,

The side s4 is:

On substituting the values,

Now, the length of the given rectangle is 5 units and width of the given rectangle is 4 units.

The area of the rectangle is:

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.