a drainage basin bordering the sea has an area of 7500 km2 . the average precipitation for this drainage basin is 900 mm year-1 . the average surface water flow at the outlet of the drainage basin equals 22.5 × 108 m3 year-1 . the average groundwater flow to the sea is 100 mm year-1 . the averages are determined for 30 hydrological years.

a. draw up the water balance.

b. determine the average actual evaporation in mm year-1 and m3 year-1

Answer with Step-by-step explanation:

The basic water balance dictates that "Amount of water flowing into the basin should be equal to the amount of water flowing out of it".

Mathematically

where

P = precipitation

I = Infiltration losses in the basin

E = Evapotranspiration

Q = is outflow from the basin

Applying the given values we get

Part b)

From the above equation we get

The evaporation in cubic meters per year is

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

step-by-step explanation: