Solve for x: |x − 2| + 10 = 12 (1 point)

a.) x = 0 and x = 4

b.) x = −4 and x = 0

c.) x = −20 and x = 4

d.) no solution

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step-by-step explanation:

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step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.