Suppose the vector-valued function r(t) = < f(t) ,g(t) ,h (t) > is smooth on an interval containing the point < f(t0) ,g(t0) ,h(t0) > . the line tangent to r(t) at t = t0 is the line parallel to the tangent vector r'(t0) that passes through < f(t0),g(t0),h(t0)> . find the line tangent to the curve at t = t0. r(t)=(2t-1,9t+5,t^2), t0= 1 the tangent line is < , , > .

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.