Linechasanequationof
y
=
-1
6
x
− 4
. parallel
tolinecisline
d ,

(10, -3) . what
istheequationofline
d ?

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

so, converting firstly the mixed fractions to improper fractions and then "adding".