You are given that a wheel has a radius of 2 feet and a spin rate of 10 revolutions per minute. describe how you would determine the linear velocity, in feet per minute, of a point on the edge of the wheel.

2.09.ft/min

Step-by-step explanation:

There is a formula for the linear velocity using rpm:

V = (2π)/60 * r * rpm

V = (2π)/60 * 2ft * 10 = 2.09ft/min

Linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

Solution:

Given that radius of wheel = 2 feet

There is a point on edge of the wheel .we need to determine linear velocity of that point.

Let’s first calculate distance covered by a point when 1 revolution of wheel is complete.

When one revolution is complete the distance traveled by a point on edge of the wheel will be equal to circumference of the wheel  

In one revolution, point covers distance of feet

So in 10 revolution, point covers distance of

Given that in a minute, wheel takes 10 revolution.

Which means in a minute , point covers feet that is feet per minute = 125.71 feet per minute

Hence linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

found it xd it ok yt