Astreet light is mounted on a pole. the tip of the shadow of a man who is standing on a street a short distance from the pole has an angle of elevation to the top of his head of 30°. a woman standing in the opposite direction of the pole as the man was standing on the same street has a angle of elevation from the tip of her shadow to her head of 41°. if the two people are 40 feet apart, how far is the street light from the head of the woman?

  21.15 ft

Step-by-step explanation:

The angle at the lamp between the two shadow tips is ...

  180° -30° -41° = 109°

This angle is opposite the 40-ft side of the triangle. The distance (d) in question is opposite the 30° angle, so can be found from the Law of Sines as ...

  d/sin(30°) = 40'/sin(109°)

  d = (40')·sin(30°)/sin(109°) ≈ 21.152'

The distance from the light to the woman's head is about 21.15 feet.

_____

We have to assume the heads are at the same height.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

answer: 193

explanation:

200-7 = 193