Find a point on the line and the line's slope. y - 2 = 2(x - 4)

Slope=2

point=(0,-6)

Step-by-step explanation:

This line is written in point slope form. Lets convert it to slope intercept (y=mx+b)

y-2=2(x-4)

1) Distribute the 2 to x and -4:

y-2=2x-8

2) Add 2 to both sides: (This is now in slope intercept form)

y=2x-6

We have now found the line's slope, 2. Lets next look for a point on the line!

We know that the y-intercept of the line is -6, so lets use that point!

The point is: (0,-6)

Footnotes:

In slope intercept form (y=mx+b), m is the slope and b is the y-intercept.

The y-intercept is the point where the line crosses the y-axis on a graph

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x