Each week, eric is supposed to prepare 4 exercises for the following week’s homework assignment. there is also a 56% chance that a visiting scholar arrives each week and engages eric with numerous research questions. during the weeks when the scholar is visiting, the number of problems eric actually writes is poisson distributed with a mean of 3.2 exercises. the number of problems eric actually creates in a week with no visitors follows a poisson distribution with mean 6.4. a. what is the probability that eric manages to create enough exercises for the following week's homework during a week with no visitors? round your answer to 4 decimal places. tries 0/5 b. if eric fails to write 4 exercises one week, what is the probability that he received a visiting scholar that week? round your answer to 4 decimal places. tries 0/5 c. in the last week of the semester, eric decides to assign every exercise he writes. given that eric writes five exercises, what is the probability that eric did not receive a visitor in the last week of the semester? round your answer to 4 decimal places.

The dolphins at the webster are fed 1/2 of a bucket of fish each day the sea otters are fed 1/2 as much fish as the dolphins how many buckets of fish are the sea fed each day? simplify you answer and write it as a proper fraction or as a whole or mixed number

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.

Consider circle o, where and . m∠bpd °. °.