John flies frequently and likes to upgrade his seat to first class. he has determined that if he checks in for his flight at least 2 hour early, the probability that he will upgrade is 0.8; otherwise, the probability that he will upgrade is 0.3. with his busy schedule, he checks in at least 2 hours before his flight only 40% of the time. at one randomly selected trip that john upgraded his seat to first class, what is the probability that he checked in at least 2 hour before the flight?

Our required probability is 0.64.

Step-by-step explanation:

Since we have given that

Let A be the event that he upgrades his seat to first class.

Let B be the event that he checks in at least 2 hours early.

Let B' be the event that he does not checks in at least 2 hours early.

So,

By using Bayes' theorem, we get that

Hence, our required probability is 0.64.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336