Where does the graph of y = sin x from x = 0 to x = 2pi start?
a. at its minimum
b. at an x-intercept
c. at its maximum d. between an x-intercept and its maximum

B

Step-by-step explanation:

Where does the graph of y = sin x from x = 0 to x = 2pi start?    (0, 0).  (0, 0) is both an x-intercept and a y-intercept.  B is the correct answer.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.