Sam creates a game in which the player rolls 4 dice. what is the probability in this game of having at least 2 of the dice land on 5.
group of answer choices

0.11500044682

0.86898036859

0.01601918459

0.13101963141

Option D

ANSWER:

Sam creates a game in which the player rolls 4 dice .The probability in this game of having at least 2 of the dice land on 5 is 0.1310196314

SOLUTION:  

We need to find the probability of atleast 2 out of 4 dices landing on 5.

For our convenience, we will calculate the probability of atleast 2 out of dices not landing on 5, later we can subtract it form 1, so that we will get the required answer.

We know that P(Event) + P (not an Event) = 1 ------------  eqn (1)

There is only one “5” on the die out of six faces. So probability of not getting a 5 on single die is =

probability of not getting a 5 any of the 4 dies is calculated by multiplying four times. So we get

Now, probability of getting a 5 on single die is =

Probability of getting a 5 any one of the 4 dies =

We have, four dies, so we can get 5 on any of them, hence we need to multiply with 4. So we get

Now, probability of atleast 2 out of dices not landing on 5 =

Using equation (1) = P(Event) + P(not an event) = 1

P(Event) + 0.8680 = 1

P(Event) = 1 – 0.8680

P(Event) = 0.1320

By observing the options we can conclude that answer is 0.1310196314

34

step-by-step explanation:

i do not know the answer

step-by-step explanation: