Find three consecutive odd integers such that the sum of the smaller two is three times larger increased by seven

three consecutive odd integers:  2n-1   2n+1   2n+3

that the sum of the smaller two is three

times larger increased by seven:                 2n-1  +  2n+1 = 3(2n+3) +7

                                                                                4n = 6n+ 9 +7

                                                                                4n = 6n+ 16

                                                                           4n -6n = 16

                                                                                -2n = 16

                                                                                   n = 16/(-2)

                                                                                   n=-8

a)   2n -1 = 2(-8) -1 = -17

b)   2n+1 = 2(-8)+1 = -15

c)   2n+1 = 2(-8)+3 = -13

Ans.   -17 ;  -15   ; -13

to find the perimeter, you add up all the lengths of the sides. in this case you would have to add up 18+22+40+80 which equals 160.

$452.90 because you needed to round to the nearest cent