British and american spelling are `rigour' and `rigor', respectively. a man staying at a parisian hotel writes this word, and a letter taken at random from his spelling is found to be a vowel. if 40% of the english-speaking men at the hotel are british and 60% are americans, what is the probability that the writer is british?

45.45%

Step-by-step explanation:

Given:

British spelling as "rigour"

here Probability of selecting vowel , P(V/B) =  

or

Probability of selecting vowel , P(V/B) =   = 0.5

and,

American spelling as "rigor"

here Probability of selecting vowel , P(V/A) =  

or

Probability of selecting vowel , P(V/A) = = 0.4

Probability of English-speaking men at hotel are British P(B) = 40% = 0.4

Probability of English-speaking men at hotel are American P(A) = 60% = 0.6

Now using Baye's theorem

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) =

or

the probability that the writer is British P(B/V) = 0.4545 = 45.45%

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

the answer is a beach is the best place to be