Abox contains 40 batteries, 5 of which have low lifetimes, 30 of which have average lifetimes, and 5 of which have high lifetimes. a consumer requires 8 batteries to run an appliance and randomly selects them all from the box. what is the probability that among the 8 batteries fitted into the consumer’s appliance, there are exactly 2 low, 4 average and 2 high lifetimes batteries?

P(2 low,4 average, 2 high) = 0.0356

Step-by-step explanation:

We are given the following information in the question:

Total number of batteries = 40

Number of batteries with average lifetime = 30

Number of batteries with low lifetime = 5

Number of batteries with high lifetime = 5

Total number of possibilities of selecting 8 batteries from 40 batteries =

Total number of possibilities of selecting 2 low lifetime batteries from 5 batteries =

Total number of possibilities of selecting 4 average lifetime batteries from 30 batteries =

Total number of possibilities of selecting 2 high lifetime batteries from 5 batteries =

Formula:

answer: .75 km

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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