Thomson proposed that negatively charged particle were randomly dispersed in a positively charged atom, much like
pieces of plum in plum pudding. rutherford shot positively charged alpha particles at thin gold foil, most of the
particles passed through unaffected.

answer:

in 1917 (in experiments reported in 1919), rutherford proved that the hydrogen nucleus is present in other nuclei, a result usually described as the discovery of the proton. earlier, rutherford learned to create hydrogen nuclei as a type of radiation produced as a yield of the impact of alpha particles on hydrogen gas; these nuclei were recognized by their unique penetration signature in air and their appearance in scintillation detectors. these experiments began when rutherford noticed that when alpha particles were shot into air (mostly nitrogen), his scintillation detectors displayed the signatures of typical hydrogen nuclei as a product. after experimentation rutherford traced the reaction to the nitrogen in air, and found that the effect was larger when alphas were produced into pure nitrogen gas. rutherford determined that the only possible source of this hydrogen was the nitrogen, and therefore nitrogen must contain hydrogen nuclei. one hydrogen nucleus was knocked off by the impact of the alpha particle, producing oxygen-17 in the process. this was the first reported nuclear reaction,    

in 1920, ernest rutherford conceived the possible existence of the neutron. in particular, rutherford examined the disparity found between the atomic number of an atom and its atomic mass. his explanation for this was the existence of a neutrally charged particle within the atomic nucleus. he considered the neutron to be a neutral double consisting of an electron orbiting a proton. in 1932, james chadwick showed uncharged particles in the radiation he used. these particles had a similar mass as protons, but did not have the same characteristics as protons. chadwick followed some of the predictions of rutherford, the first to work in this then unknown field.

step-by-step explanation:

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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