Unlike a decreasing geometric series, the sum of the harmonic series 1, 1/2, 1/3, 1/4, 1/5, . . di- log(n! ) = θ(n log n). verges; that is, it turns out that, for large n, the sum of the first n terms of this series can be well approximated as 1 ≈ ln n + γ, i=1 i where ln is natural logarithm (log base e = 2.718 . .) and γ is a particular constant 0.57721 . .. showthat 1 = θ(logn). i=1 i (hint: to show an upper bound, decrease each denominator to the next power of two. for a lower bound, increase each denominator to the next power of 2.)

i am thinking c. sorry if im wrong .

step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours