20 points
the slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. what is the
point-slope form of the equation for this line?
o y + 13 = 5(x + 2)
oy- 13 = 5(x - 2)
oy- 2 = 5(x - 13)
o
y + 2 = 5(x + 13)

y + 13 = 5(x + 2)

Step-by-step explanation:

The given equation is in slope- intercept form, that is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x - 3 has slope m = 5

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Using m = 5 and (a, b) = (- 2, - 13), then

y - (- 13) = 5(x - (- 2)), that is

y + 13 = 5(x + 2) ← in point- slope form

answer: .75 km

step-by-step explanation:

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb