Round each number to the nearest whole number. then
use the appropiate symbol to compare the rounded numbers.
368.35 and 368.32

On rounding first number 368.35 we get 368  

On rounding second number 368.32 we get 368.

368=368 so appropriate comparison operator is “=”.

Solution:

Need to round two given numbers.

First number is 368.35

Given number resides between two whole numbers 368 and 369.

If three numbers are visualize on number line,it can be said that 368.35 is more closer to 368 than 369. And as we need to round the number to nearest whole number. On rounding 368.35 we get 368.

Second number is 368.32

Given number resides between two whole numbers 368 and 369.

If three numbers are visualize on number line, it can be said that 368.32 is more closer to 368 than 369. And as we need to round the number to nearest whole number. On rounding 368.32 we get 368.

On rounding first number 368.35 we get 368  

On rounding second number 368.32 we get 368.

That is both the output is same after rounding.

On comparison we get 368 = 368. So required appropriate comparison operator is “=”.

1,645,493,059.35

step-by-step explanation:

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: