Write the equation of a line that is perpendicular to the given line and that passes through the given point.
-3x - 5y = 17; (6, 3)
y=2x-9
y = 2x - 9
y = -2x - 9
y = 2x + 0

y - 3 = (5/3)(x - 6)

Step-by-step explanation:

The usual first step is to determine the slope of the given line.

In this case the slope is -3/5.

A line perpendicular to this given line would have a slope of 5/3, which is the negative reciprocal of -3/5.

This new line goes thru (6, 3) and has a slope of 5/3.  Thus, the equation of the line in point-slope form is

y - 3 = (5/3)(x - 6)

Double check that you have copied the problem down correctly.  The slope of the line represented by -3x - 5y = 17 is neither 2 nor -2; it is -3/5, and so the slope of a line perpendicular to -3x - 5y = 17 is +5/3.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.