Graph a line with a slope of 1/4 that contains the point (6, 3).

The equation of the line is:

The graph is given at the end.

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The equation of a line has the following format:

In which

In this problem:

Thus

The graph is given at the end.

A similar problem is given at link

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

we have

substitute

The easiest way to graph a line is to calculate the intercepts

The x-intercept is the value of x when the value of y is equal to zero

For y=0

The x-intercept is the point (-6,0)

The y-intercept is the value of y when the value of x is equal to zero

For x=0

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

32

step-by-step explanation: