Heights of women have a bell-shaped distribution with a mean of 156cm and a standard deviation of 5cm. using chebyshev's theorem, what do we know about the percentage of women with heights that are within 2standard deviations of the mean? what are the minimum and maximum heights that are within 2standard deviations of the mean? at least nothing%of women have heights within 2standard deviations of 156cm.(round to the nearest percent as needed.)the minimum height that is within 2standard deviations of the mean is nothingcm. the maximum height that is within 2standard deviations of the mean is nothingcm.

At least (1-(1/3)^2)% = 89% of the data is within 3 std  of the mean ( The rest is not really needed)  Minimum is 159-3*6 = 141 cm , maximum is 159 + 3*6 = 177 cm .At least 89 % of women have heights within 33 standard deviations of 159 cm. (Round to the nearest percent as needed.) The minimum height that is within 33 standard deviations of the mean is  141 cm. The maximum height that is within 33 standard deviations of the mean is  177 cm. ( This might help.)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

-2x-4

step-by-step explanation: