Afactory produces 90 packages of mixed nuts in 1 min. a quality control manager selected 8 of these 90 packages at random and then counted the number of nuts in each package. the manager recorded the results.
31, 31, 32, 33, 35, 35, 35, 36
what is the estimated median number of nuts in all 90 packages?

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this