Which of the following steps were applied to abcd to obtain a'b'c'd'?

It was reflected, when a figure is reflected, all points along each segment are reflected. In other words, a point lying on AB in the pre-image will lie on A'B' in the image. If point E is the midpoint of AB, then point E' will be the midpoint of A'B'. Therefore, a reflected figure preserves collinearity and betweenness of points, just like with translated figures. Also, if a line of symmetry exists in the pre-image, it will exist in the image.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.