The formula for the number of multisets is (n k−1)! divided by a product of two other factorials. we want to use the quotient principle to explain why this formula counts multisets. the formula for the number of multisets is also a binomial coefficient, so it should have an interpretation that involves choosing k items from n k−1 items. the parts of the problem that follow lead us to these explanations. a. in how many ways can you place k red checkers and n−1 black checkers in a row?

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

answer: apothems is your answer

step-by-step explanation: hope u get it right

step-by-step explanation: