You are designing a container in the shape of a cylinder. the radius is 5 inches. you want the container to hold at least 725π cubic inches. what is the least possible height of the container?

The answer to your question is: h = 14.5 in

Step-by-step explanation:

Data

radius = 5 in

Volume = 725 π in³

height = ?

Formula

               Volume = 2πr²h

Substitution

                     725 π in³ = 2πr² h

                    h = 725π / 2πr²

                    h = 725 / 2(5)²

                    h = 725 / 50

                    h = 14.5 in

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!