Amanufacturer of matches randomly and independently puts 22 matches in each box of matches produced. the company knows that one-tenth of 5 percent of the matches are flawed. what is the probability that a matchbox will have one or fewer matches with a flaw?

The probability that a matchbox will have one or fewer matches with a flaw is 0.9946 approximately.    

Step-by-step explanation:

Consider the provided information.

A manufacturer of matches randomly and independently puts 22 matches in each box of matches produced. The company knows that one-tenth of 5 percent of the matches are flawed.

One-tenth of 5 percent can be written as 0.5%

Here we have the value of n=22 and the value of p=0.5%=0.005

We want the probability that a matchbox will have one or fewer matches with a flaw.

That means

Thus the required probability is:

Hence, the probability that a matchbox will have one or fewer matches with a flaw is 0.9946 approximately.

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.