An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet in the air. the motion of the object can be modeled using the function f(t)=−16t2+64t+16, where t is the time in seconds and f(t) is the height of the object. when, in seconds, will the object reach its maximum height? do not include units in your answer.

After 2 seconds the object reach its maximum height of 80 feet.

Step-by-step explanation:

Consider the provided function.

The function is a downward parabola.

The object will reach its max height at the vertex of the parabola.

The vertex of the parabola is given by ,

Where the standard form is .

By comparing the provided function with the standard form.

a=-16, b=64 and c=16

Thus, the vertex are:

Now substitute the value of t in the provided function.

Hence, after 2 seconds the object reach its maximum height of 80 feet.

answer: 26

step-by-step explanation:

well, michelle wanted to measure the height of her school's flagpole she placed a mirror on the ground 48 feet from the flagpole then walk backwards until she was able to see the top of the pole in the mirror her eyes were 5 feet above the ground and she was 12 ft from the mirror using similar triangles find the height of the flagpole to the nearest tenth of a foot find the geometric mean of them pair of numbers. its easy math