Atortoise and a hare are competing in a 1600-meter race. the arrogant hare decides to let the tortoise have a 510-meter head start. when the start gun is fired the hare begins running at a constant speed of 8 meters per second and the tortoise begins crawling at a constant speed of 5 meters per second. define a function f to represent the tortoise's distance from the finish line (in meters) in terms of the number of seconds t since the start of the race.

f(t) = 1090 - 5t

Step-by-step explanation:

A tortoise and a hare are competing in a 1600 meter race but the tortoise is 510 meter ahead of hare.

If tortoise traveled in 't' seconds after the start gun was fired, total distance covered = Speed × times

= 5t meters

Since distance of the tortoise from the start line is = 510 meter

So, the distance at which the tortoise will reach after the start gun = (510 + 5t) meter

Now the distance of tortoise from the finish line = 1600 - (510 + 5t)

= 1600 - 510 - 5t

= (1090 - 5t)

If a function 'f' defines the tortoise's distance from the finish line then the function will be f(t) = (1090 - 5t)

answer: she must produce at least 9,000 windows in order to make a profit of $48,000

explanation:

48,000 - 12,000 = 36,000

36,000/4 = 9,000