Probability with or

the us safety administration report on pedestrian injuries in traffic accidents found the following statistics: of the cases reported, in 37.1% the victim was under 16 years old, in 27.5% the accident occured at night, and in 3.8% the victim was under 16 and the accident occurred at night.
round answers to the nearest 10th of a percent

1) what is the probability that the victim was under 16 or the accident occurred at night?

2) what is the probability that the victim was 16 or older and the accident occurred during the day?

Step-by-step explanation:

It is convenient to put the numbers into a table and fill in the remaining values. In the attachment, the given numbers are blue. The black numbers are the values that make the totals add up.

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1. The probability of interest is the sum of the numbers in the table spaces shaded blue. You can find that sum several ways. The usual way used for an "OR" probability is ...

  p(<16 or night) = p(<16) + p(night) - p(<16 & night)

  = 37.1% + 27.5% - 3.8%

  = 60.8%

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2. This probability is the complement of the one in the first part. It is the value in the yellow-shaded box.

  p(≥16 & day) = 1 - p(<16 or night) = 1 -60.8% = 39.2%

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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