Abox is to be constructed with a rectangular base and a height of 5 cm. if the rectangular base must have a perimeter of 28 cm, which quadratic equation best models the volume of the box?

v = lwh
p = 2(l + w)
y = 5(28 – x)(x)
y = 5(28 – 2x)(x)
y = 5(14 – x)(x)
y = 5(14 – 2x)(x)

y=5(14-x)(x)

Step-by-step explanation: The perimeter is 2a + 2b (where a and b are the sides)

We know that 28=2a +2b

14=a + b

a= 14-b

So the volume is height*side*side= 5* b * (14-b)

The solution equation is the same just uses x instead of a or b

the thermometer is precise but not accurate

step-by-step explanation:

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.