The domain of the following relation r{(6, -2), (1, 2), (-3.-4), (-3, 2)} is
{-3,-3,1,6}
{-4,-2,2,2}
{-4,-2, 2}
{-3,1,6}

For this case we have that by definition, the domain of a function is given by all the values of "x" for which the function is defined.

In this case we have:

Thus, it is observed that the values of "x" of the relation R are given by:

Therefore, the domain is: {-3,1,6}

Option D

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.