Mathematics, 12.10.2019 01:30 mckinzirauch9
The distribution of weekly salaries at a large company is reverse j-shaped with a mean of $1000 and a standard deviation of $370. suppose you want to calculate the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75. which distribution would you use to solve the problem?
Answers: 1
![n = [z\times \frac{s}{E}]^2](/tpl/images/0311/8956/adf8b.png)
![80 = [z \times \frac{370}{75}]^2](/tpl/images/0311/8956/f2560.png)
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