The left and right page numbers of an open book are two consecutive integers whose sum is 417. find these page numbers.

➷  We can form an equation:

n + n + 1 = 417

Simplify this:

2n + 1 = 417

-1 from both sides

2n = 416

Divide both sides by 2:

n = 208

Thus, the two page numbers are 208 and 209.

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ANSWER:

The page numbers are 208 and 209

SOLUTION:

Given, the left and right page numbers of an open book are two consecutive integers whose sum is 417.  

We need to find these page numbers.  

Let, the left page number value be x

Then, the right page number value becomes x + 1, because right page comes after the left page while numbering and as they are consecutive, value of right page number is greater than left page number.

Now, according to the given information,  

left page number + right page number = 417

x + (x + 1) = 417

x + x + 1 = 417

2x + 1 = 417

2x = 417 – 1

2x = 416

x =

x = 208

left page number is 208

Now, right page number is (x + 1) = 208 + 1 = 209

Hence, the page numbers are 208 and 209

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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