Find the equation of the line that contains the point p(4,0) and is perpendicular to the graph of 3x-2y+5

need now! show work

y = -2/3x + 8/3

Step-by-step explanation:

3x - 2y + 5? I am assuming you mean 3x - 2y = 5, so this answer is based on this equation.

3x - 2y = 5

-2y = -3x + 5

2y = 3x - 5

y = 3/2x - 5/2

3/2 = -2/3 (This is the perpendicular slope)

(4,0)

y - y1 = m(x - x1)

y - 0 = -2/3(x - 4)

y = -2/3x + 8/3

So the equation would be y = -2/3x + 8/3.

You can check the equations by graphing them:

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.