Need

a stadium has 49,000 seats. seats sell for $30 in section a, $24 in section b, and $18 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,246,800 from each sold-out event. how many seats does each section hold?

Step-by-step explanation:

Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.

The revenue from those seats is, ...

  24,500×$30 = $735,000

so the revenue from B and C seats is ...

  $1,246,800 -735,000 = $511,800

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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...

  24b +18(24500-b) = 511800

  6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms

  b = 70,800/6 = 11,800 . . . . . . . seats in B section

  24,500 -11,800 = 12,700 . . . . . seats in C section

There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

answer: i think it's a

step-by-step explanation: