The mars cereal company has two different cereal boxes for mars cereal. the large box is 8 inches wide, 11 inches high, and 3 inches deep. the small box is 6 inches wide, 10 inches high, and 2.5 inches deep.
a. how much more cardboard is needed to make the large box than the small box?
b. how much more cereal does the large box hold than the small box?

a)90  square inches

b)104 cubic inches

Step-by-step explanation:

Dimensions of the bigger box

W= 8 in

H=11 in

D= 3 in

Dimensions of the smaller box

w= 6 in

h= 10 in

h= 2.5 in

therefore, difference in the area of the cupboard

=2[ WH+HD+WD] - 2[wh+hd+wd]

= 2[8*11+11*3+8*3]- 2[6*10+10*2.5+6*2.5]

=290- 200= 90 square inches

volume of the large cupboard = WHD= 8*11*3= 264 cubic in

volume of the small cupboard= whd= 6*10*2.5= 150 cubic in

therefore,  264-150= 114 cubic in more cereal does the large box hold than the small box

I am kind of confused what is the final awsner

Step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

step-by-step explanation:

duck you