Error analysis describe and correct the error
student made when solving. kx + 3x = 4 for x.

kx + 3x = 4
kx + 3x - 3x = 4 - 3x
kx=4 - 3x
- 3x
x = 4*3* x

Solving

for x

Step-by-step explanation:

here the student leave 'x' in both sides

The error is not notice the factor is the 'x'

So:

Is the best way to solving to 'x' 'k' maybe is knowing o is a constant

`1234567890-=/*-qwertyuiop[]asdfghjkl; '\\zxcvbnm,./+ /

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4