In a large population, 76% of the households have cable tv. a simple random sample of 225 households is to be contacted and the sample proportion computed. what is the probability that the sampling distribution of sample porportions is less than 82%?

0.017559

Step-by-step explanation:

Data provided:

Probability of Households Having cable TV, p₀ = 76% = 0.76

Therefore,

The probability that the Households not having cable TV = 1 - 0.76 = 0.24

Sample size, n = 225 households

sample proportions is less than 82% i.e p = 0.82

Now,

The standard error, SE =

or

SE =

or

SE = 0.02847

and,

or

or

Z = 2.107

therefore,

P(sample porportions < 0.82) = P(Z < 2.107)

now from the p value from the Z table

we get

P(sample porportions < 0.82) =  0.017559

which expression represents the approximate length of bc?

step-by-step explanation:

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: