4. triangle abc has vertices a(-2, 0), b(0, 3), and c(2, 3) and is dilated by a factor of 2 using
the point (0, -1) as the point of dilation. the dilated triangle is named aa'b'c: what are
the coordinates of the vertices of the resulting triangle?

Step-by-step explanation:

When the dilation factor is k and the center of dilation is (a, b), the transformation relation is ...

  (x, y) ⇒ (a, b) + k((x, y) -(a, b)) = (kx +(1-k)a, ky +(1-k)b)

For k=2, (a, b) = (0, -1) the transformation is ...

  (x, y) ⇒ (2x, 2y +1)

So, the given vertices are dilated to ...

  A(-2, 0) ⇒ (2(-2), 2(0)+1) = A'(-4, 1)

  B(0, 3) ⇒ (2(0), 2(3)+1) = B'(0, 7)

  C(2, 3) ⇒ (2(2), 2(3)+1) = C'(4, 7)

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

95.03 is the answer. hope this !