An accident at an oil drilling platform is causing a circular oil slick. the slick is 0.07 foot thick, and when the radius of the slick is 110 feet, the radius is increasing at the rate of 0.9 foot per minute. at what rate (in cubic feet per minute) is oil flowing from the site of the accident? (round your answer to two decimal places.)

Step-by-step explanation:

Given

Thickness of oil slick=0.07 foot

radius of slick=110 ft

Let V be the volume of oil slick

so,

rate of oil flowing is

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.